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(B) $1$. In the given figure,the two springs with spring constant $k_1$ are connected in parallel. The equivalent spring constant of these two springs

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$ \left[ \frac{1}{2k_1} + \frac{1}{k_2} \right]^{-1} $

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(B) $1$. In the given figure,the two springs with spring constant $k_1$ are connected in parallel. The equivalent spring constant of these two springs is $k_p = k_1 + k_1 = 2k_1$.$2$. This equivalent spring $k_p$ is then connected in series with the spring having spring constant $k_2$.$3$. For two springs connected in series,the equivalent spring constant $k_{eq}$ is given by $\frac{1}{k_{eq}} = \frac{1}{k_p} + \frac{1}{k_2}$.$4$. Substituting $k_p = 2k_1$,we get $\frac{1}{k_{eq}} = \frac{1}{2k_1} + \frac{1}{k_2}$.$5$. Therefore,$k_{eq} = \left[ \frac{1}{2k_1} + \frac{1}{k_2} \right]^{-1}$.

The total spring constant of the system as shown in the figure will be

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